Deep Dive: E7D07
The correct answer is A: It bypasses rectifier output ripple around D1. What is the purpose of C2 in the circuit shown in Figure E7-2 is that it bypasses rectifier output ripple around D1. C2 filters the ripple from the rectifier. For amateur radio operators, this is important for power supply design. Understanding this helps when analyzing regulator circuits.
Why Other Answers Are Wrong
Option B: Incorrect. Brute force filter for output isn't the purpose - C2 bypasses ripple around D1. Brute force filter isn't the purpose. Option C: Incorrect. Preventing self-oscillation isn't the purpose - C2 bypasses ripple around D1. Self-oscillation isn't the purpose. Option D: Incorrect. Providing fixed DC bias for Q1 isn't the purpose - C2 bypasses ripple around D1. DC bias isn't the purpose.
Exam Tip
C2 in Figure E7-2 purpose = bypasses rectifier output ripple around D1. Think 'C'2 = 'B'ypasses 'R'ipple. C2 filters the ripple from the rectifier. Not brute force filter, not self-oscillation, not DC bias - just bypasses ripple.
Memory Aid
C2 in Figure E7-2 purpose = bypasses rectifier output ripple around D1. Think 'C'2 = 'R'ipple 'B'ypass. C2 filters the ripple from the rectifier. Important for power supply design.
Real-World Example
C2 in the circuit shown in Figure E7-2: Its purpose is to bypass rectifier output ripple around D1. C2 filters out the AC ripple from the rectified DC. This is the purpose - bypasses ripple.
Source & Coverage
Question Pool: 2024-2028 Question Pool
Subelement: E7D
Reference: 2024-2028 Question Pool · E7 - Practical Circuits
Key Concepts
Official Pool Source
Question text and answer key are synchronized with the current NCVEC Extra Class pool and mapped to the E7D topic.