Deep Dive: E7G09
The correct answer is D: -2.3 volts. For the inverting op-amp circuit in Figure E7-3, the output voltage is calculated as Vout = -(RF / R1) × Vin, where the negative sign indicates inversion. With R1 = 1,000 ohms, RF = 10,000 ohms, and Vin = 0.23 volts DC: Gain = -RF / R1 = -10,000 / 1,000 = -10. Output = -10 × 0.23 = -2.3 volts. The output is inverted (negative) and amplified by a factor of 10. This is the standard calculation for an inverting op-amp: multiply the input by the negative of the gain ratio.
Why Other Answers Are Wrong
Option A: Incorrect. 0.23 volts is just the input voltage, not the output. The output is amplified and inverted. Option B: Incorrect. 2.3 volts would be the output if it weren't inverted, but the inverting amplifier produces a negative output. Option C: Incorrect. -0.23 volts would be the output if the gain were -1, but with RF = 10k and R1 = 1k, the gain is -10.
Exam Tip
Inverting op-amp output = -(RF/R1) × Vin. Remember: For an inverting op-amp, Vout = -(RF/R1) × Vin. With RF=10k, R1=1k, Vin=0.23V: Vout = -10 × 0.23 = -2.3V.
Memory Aid
**I**nverting **O**utput = **N**egative **G**ain × **I**nput (think 'IO = NGI' = Negative Gain × Input)
Real-World Example
You're using an inverting op-amp with R1 = 1kΩ and RF = 10kΩ to amplify a 0.23-volt DC signal. The gain is -10, so the output is -2.3 volts. The negative sign indicates the signal is inverted - a positive input produces a negative output.
Source & Coverage
Question Pool: 2024-2028 Question Pool
Subelement: E7G
Reference: FCC Part 97.3
Key Concepts
Official Pool Source
Question text and answer key are synchronized with the current NCVEC Extra Class pool and mapped to the E7G topic.
