Deep Dive: E9E08
The correct answer is C: To divide power equally between two 50-ohm loads while maintaining 50-ohm input impedance. A Wilkinson divider is a matched RF power divider or combiner. Its transmission-line sections and isolation resistor provide equal division, a matched input, and isolation between the output ports at the design frequency.
Why Other Answers Are Wrong
Option A: A Wilkinson divider divides RF power, not operating frequency. Option B: Feeding a high-impedance antenna from a low-impedance source is not the use described by this question. Option D: Extending a counter's frequency range requires a frequency divider, not a Wilkinson power divider.
Exam Tip
Wilkinson means equal RF power split with a matched input and isolated output ports.
Memory Aid
Wilkinson: split power, keep 50 ohms.
Source & Coverage
Question Pool: 2024-2028 Question Pool
Subelement: E9E
Reference: 2024-2028 Question Pool · E9 - Antennas and Transmission Lines
Key Concepts
Official Pool Source
Question text and answer key are synchronized with the current NCVEC Extra Class pool and mapped to the E9E topic.