Deep Dive: E1A03
The correct answer is C: 14.1472 MHz. The authorized 20-meter data segment ends at 14.150 MHz. A 2.8 kHz wide upper-sideband data signal extends upward from the displayed carrier frequency, so subtracting 2.8 kHz from 14.150 MHz gives a highest legal carrier frequency of 14.1472 MHz.
Why Other Answers Are Wrong
Option A: 14.0708 MHz is legal but is not the highest possible carrier frequency. Option B: 14.1002 MHz is also below the highest possible carrier frequency. Option D: A 2.8 kHz USB data signal at 14.3490 MHz is outside the authorized 20-meter data segment.
Exam Tip
For USB at an upper band edge, subtract the full occupied bandwidth: 14.1500 - 0.0028 = 14.1472 MHz.
Memory Aid
14.150 minus 2.8 kHz equals 14.1472 MHz.
Source & Coverage
Question Pool: 2024-2028 Question Pool
Subelement: E1A
Reference: [97.305, 97.307(b)]
Key Concepts
Official Pool Source
Question text and answer key are synchronized with the current NCVEC Extra Class pool and mapped to the E1A topic.